Question
Factorise:
$14 x^3+21 x^4 y-28 x^2 y^2$

Answer

$14 x^3+21 x^4 y-28 x^2 y^2$
$=14 x^2\left(2 x+3 x^2 y-4 y^2\right)(\text { HCF of } 14,21,28=7)$

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