Question
Factorise:
$21 x^2+5 x-6$
$21 x^2+5 x-6$
✓
Answer
$21 x^2+5 x-6$
$=21 x^2+14 x-9 x-6$
$=7 x(3 x+2)-3(3 x+2)$
$=(3 x+2)(7 x-3)$
$=21 x^2+14 x-9 x-6$
$=7 x(3 x+2)-3(3 x+2)$
$=(3 x+2)(7 x-3)$
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