Question
Factorise:
$24 x^2-41 x+12$
$24 x^2-41 x+12$
✓
Answer
$24 x^2-41 x+12$
$=24 x^2-32 x-9 x+12$
$=8 x(3 x-4)-3(3 x-4)$
$=(3 x-4)(8 x-3)$
$=24 x^2-32 x-9 x+12$
$=8 x(3 x-4)-3(3 x-4)$
$=(3 x-4)(8 x-3)$
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