Question
Factorise:$2\text{x}^2-\text{x}+\frac{1}{8}$

Answer

$2\text{x}^2-\text{x}+\frac{1}{8}$$=2\text{x}^2-\frac{1}{2}\text{x}-\frac{1}{2}\text{x}+\frac{1}{8}$
$=\frac{\text{x}}{2}(4\text{x}-1)-\frac{1}{8}(4\text{x}-1)$
$=\Big(\frac{\text{x}}{2}-\frac{1}{8}\Big)(4\text{x}-1)$

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