Question
Factorise:$\text{x}^2+7\sqrt{6}+60$
✓
Answer
$\text{x}^2+7\sqrt{6}+60$$=\text{x}^2+2\sqrt{6}\text{x}+5\sqrt{6}\text{x}+60$
$=\text{x}(\text{x}+2\sqrt{6})+5\sqrt{6}(\text{x}+2\sqrt{6})$
$=(\text{x}+2\sqrt{6})(\text{x}+5\sqrt{6})$
$=\text{x}(\text{x}+2\sqrt{6})+5\sqrt{6}(\text{x}+2\sqrt{6})$
$=(\text{x}+2\sqrt{6})(\text{x}+5\sqrt{6})$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
If $\text{x}-\frac{1}{\text{x}}=-1$ find the value of $\text{x}^2+\frac{1}{\text{x}^2}.$
→Find the value of x in the following:$\sqrt[5]{5\text{x}+2}=2$
→In the given figure, line PS is a transversal of parallel line AB and line CD. If Ray QX, ray QY, ray RX, ray RY are angle bisectors, then prove that □ QXRY is a rectangle.
Given: line AB || line CD
Rays QX, RX, QY, RY are the bisectors of ∠AQR, ∠QRC, ∠BQR and ∠QRD respectively.
To prove: □QXRY is a rectangle.
Compute the value of x in the following figures.
If $\text{x}=3+2\sqrt2,$ than find the value of $\sqrt{\text{x}}-\frac{1}{\sqrt{\text{x}}}.$
→Side of a cube is 4.5 cm . Find the surface area of all vertical faces and total surface area of the cube.
Given: Side of cube $(I)=4.5 cm$
To find: Surface area of all vertical faces and the total surface area of the cube
→Given: Side of cube $(I)=4.5 cm$
To find: Surface area of all vertical faces and the total surface area of the cube
Express the following equation in the form ax + by + c = 0 and indicate the values of a, b, c in case.$\frac{\text{x}}{5}-\frac{\text{y}}{6}=1$
→Convert into Decimal form the rational numbers And Write is either terminating or non-terminating recurring type :$\frac{2}{5}$
→Find the values of : $5 \sin 30^{\circ}+3 \tan 45^{\circ}$
→Multiply:$6\sqrt{15}$ by $4\sqrt{3}$
→