Question
Factorise:
2x4 - 32
2x4 - 32
✓
Answer
2x4 - 32
= 2(x4 - 16)
= 2[(x2)2 - (4)2]
= 2[(x2 - 4)(x2 + 4)]
= 2[(x2 - 22)(x2 + 4)]
= 2[(x - 2)(x + 2)(x2 + 4)]
= 2(x - 2)(x + 2)(x2 + 4)
= 2(x4 - 16)
= 2[(x2)2 - (4)2]
= 2[(x2 - 4)(x2 + 4)]
= 2[(x2 - 22)(x2 + 4)]
= 2[(x - 2)(x + 2)(x2 + 4)]
= 2(x - 2)(x + 2)(x2 + 4)
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