Question
Factorise:
3a3b - 243ab3
3a3b - 243ab3
✓
Answer
3a3b - 243ab3
= 3ab(a2 - 81b2)
= 3ab[(a)2 - (9b)2]
= 3ab(a + 9b)(a - 9b) $\big[\therefore\ \text{a}^2-\text{b}^2=(\text{a}-\text{b})(\text{a}+\text{b})\big]$
= 3ab(a2 - 81b2)
= 3ab[(a)2 - (9b)2]
= 3ab(a + 9b)(a - 9b) $\big[\therefore\ \text{a}^2-\text{b}^2=(\text{a}-\text{b})(\text{a}+\text{b})\big]$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Factorise:
8a3 + 125b3 - 64c3 + 120abc
8a3 + 125b3 - 64c3 + 120abc
The mean weight of 6 boys in a group is 48kg The individual weights of five of them are 51kg, 45kg, 49kg, 46kg and 44kg. Find the weight of the sixth boy.
Evaluate the product without multiplying directly: $104 \times 96$
→Examine whether the following numbers are rational or irrational.
$\sqrt{\frac{13}{117}}$
→$\sqrt{\frac{13}{117}}$
If a and b are distinct primes such that $\sqrt[3]{\text{a}^6\text{b}^{-4}}=\text{a}^\text{x}\text{b}^{2\text{y}},$find x and y.
→Rationalise the denominator of $\frac{5}{\sqrt{3}-\sqrt{5}}$
→How many planes can be made to pass through three distinct points?
Find the zeroes of the polynomial:
p(x) = (x - 2)2 - (x + 2)2
p(x) = (x - 2)2 - (x + 2)2
Find five different solution of the following equations:
→$\frac{2\text{x}}{5}+\frac{3\text{y}}{10}=3$