Question
Factorise:
8a3 + 125b3 - 64c3 + 120abc

Answer

8a3 + 125b3 - 64c3 + 120abc
= (2a)3 + (5b)3 + (-4c)3 - 3 × (2a) × (5b) × (-4c)
= (2a + 5b - 4c)[(2a)2 + (5b)2 + (-4c)2 - (2a)(5b) - (5b)(-4c) - (2a) × (-4c)]
= (2a + 5b - 4c)(4a2 + 25b2 + 16c2 - 10ab + 20bc + 8ac)

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