Question
Factorise$ : (3x - 2y)^2+ 3 (3x - 2y) - 10$
✓
Answer
$(3x - 2y)^2+ 3 (3x - 2y) - 10$
Assume that $3x - 2y = a$
Therefore, $(3x - 2y)^2+ 3 (3x - 2y) - 10$
$= a2 + 3a - 10$
$= a2 + 5a - 2a -10$
$= a( a + 5 ) -2 ( a + 5 )$
$= ( a + 5 )( a - 2 )$
$= ( 3x - 2y + 5 )( 3x - 2y - 2)$
Assume that $3x - 2y = a$
Therefore, $(3x - 2y)^2+ 3 (3x - 2y) - 10$
$= a2 + 3a - 10$
$= a2 + 5a - 2a -10$
$= a( a + 5 ) -2 ( a + 5 )$
$= ( a + 5 )( a - 2 )$
$= ( 3x - 2y + 5 )( 3x - 2y - 2)$
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