Question
Factorise:
$3 z^2-10 z+8$

Answer

$3 z^2-10 z+8$
$=3 z^2-6 z-4 z+8$
$\{24=3 \times 8,24=(-6) \times(-4),-10=-6-4\}$
$=3 z(z-2)-4(z-2)$
$=(z-2)(3 z-4)$

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