Question
Factorise:
$4 a^2-9 b^2-2 a-3 b$
$4 a^2-9 b^2-2 a-3 b$
✓
Answer
$4 a^2-9 b^2-2 a-3 b$
$=(2 a)^2-(3 b)^2-(2 a+3 b)$
$=(2 a-3 b)(2 a+3 b)-(2 a+3 b)$
$=(2 a+3 b)(2 a-3 b-1)$
$=(2 a)^2-(3 b)^2-(2 a+3 b)$
$=(2 a-3 b)(2 a+3 b)-(2 a+3 b)$
$=(2 a+3 b)(2 a-3 b-1)$
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