Question
Factorise:
$4 x^2-9 y^2$
$4 x^2-9 y^2$
✓
Answer
$4 x^2-9 y^2$
$=(2 x)^2-(3 y)^2$
$=(2 x+3 y)(2 x-3 y)$
$\left\{\because a^2-b^2=(a+b)(a-b)\right\}$
$=(2 x)^2-(3 y)^2$
$=(2 x+3 y)(2 x-3 y)$
$\left\{\because a^2-b^2=(a+b)(a-b)\right\}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Find the volume of a cuboid whose:
Length $=12 cm$, breadth $=8 cm$, height $=6 cm$
→Length $=12 cm$, breadth $=8 cm$, height $=6 cm$
Represent the following numbers on the number line.
$5\frac{5}{7}$
→$5\frac{5}{7}$
Using laws of indices, write proper numbers in the following boxes.
→$\left(\frac{5}{7}\right)^{-3}=\left(\frac{()}{()}\right)^3$
Evaluate:$\sqrt{10.0489}$
→Factorise:
$x^2+8 x+16$
→$x^2+8 x+16$
Simplify:
$\frac{4}{9}\div\frac{-5}{12}$
→$\frac{4}{9}\div\frac{-5}{12}$
Working 8 hours a day, Ashu can copy a book in 18 days. How many hours a day should he work so as to finish the work in 12 days?
Find the continues products:
$(2 p+3)(2 p-3)\left(4 p^2+9\right)$
→$(2 p+3)(2 p-3)\left(4 p^2+9\right)$
Solve:
$x^8-1$
→$x^8-1$
Find the measure of each exterior angle of a regular:
Hexagon.
Hexagon.