Question
Find the continues products:
$(2 p+3)(2 p-3)\left(4 p^2+9\right)$

Answer

$(2 p+3)(2 p-3)\left(4 p^2+9\right)$
$\left((2 p)^2-(3)^2\right)\left(4 p^2+9\right)$
$\left(4 p^2-9\right)\left(4 p^2+9\right)$
$\left(4 p^2\right)^2-(9)^2$
$16 p^4-8$

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