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Factorization — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSFactorization2 Marks
Question
Factorise: $4y^2– 12y + 9$, using the identity $a^2- 2ab + b^2= (a - b)^2$
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Answer

Using identity, $a^2-2 a b+b^2=(a-b)^2$
$4 y^2-12 y+9$
$=(2 y)^2-2 \times 3 \times(2 y)+(3)^2$
$=(2 y-3)^2$
= (2y – 3)(2y – 3)
This is the required factorisation.

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