Question
Find the largest number of $2$ digits which is a perfect square.
✓
Answer
The first three digit number $(100)$ is a perfect square. Its square root is $10.$
The number before $10$ is $9.$
Square of $9 = (9)^2= 81$
Thus, the largest 2 digit number that is a perfect square is $81.$
The number before $10$ is $9.$
Square of $9 = (9)^2= 81$
Thus, the largest 2 digit number that is a perfect square is $81.$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Find the following products:
$ \left(x^2+x y+y^2\right) \times(x-y) $
→$ \left(x^2+x y+y^2\right) \times(x-y) $
Convert each part of the ratio to percentage:$3: 1$
→In which of the following tables $x$ and $y$ vary inversely:
→|
$x$
|
$4$ | $3$ | $6$ | $1$ |
|
$y$
|
$9$ | $12$ | $8$ | $36$ |
Find a few numbers that leave a remainder of 2 when divided by 3 and a remainder of 2 when divided by 4. Write an algebraic expression to describe all such numbers.
Express the following rational numbers in standard form. $\frac{24}{-64}$
→Find the multiplicative inverse (reciprocal) of the following rational numbers: $\frac{-5}{8}\times\frac{16}{15}$
→Subtract: $-3p2 + 3pq + 3px$ from $3p(-p - a - r)$
→Express $\frac{-48}{60}$ as a rational number with denominator $5.$
→What is the sum of all interior angles of a regular: Polygon of $12$ sides?
→Put three different numbers in the circles so that when you add the numbers at the end of each line you always get a perfect square. 