Question
Factorise:
$63 a^2-112 b^2$

Answer

Using: $a ^2- b ^2=( a + b )( a - b )$
$63 a^2-112 b^2$
$=7\left(9 a^2-16 b^2\right)$
$=7\left[(3 a)^2-(4 b)^2\right.$
$=7(3 a+4 b)(3 a-4 b)$

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