Question
Factorise $:64 - a^3b^3$

Answer

$64 - a^3b^3$
$= (4)^3 - (ab)^3$
$= ( 4 - ab )[(4)^2 + 4 x ab + (ab)^2 ] [ \because a^3 - b^3 = ( a - b )( a^2 + ab + b^2 )]$
$= ( 4 - ab )( 16 + 4ab + a^2b^2 )$

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