Question
Factorise:
$6 a b-b^2+12 a c-2 b c$
$6 a b-b^2+12 a c-2 b c$
✓
Answer
$6 a b-b^2+12 a c-2 b c$
$=6 a b+12 a c-b^2-2 b c$
$=6 a(b+2 c)-b(b+2 c)$
$= (b + 2c)(6a - b)$
$=6 a b+12 a c-b^2-2 b c$
$=6 a(b+2 c)-b(b+2 c)$
$= (b + 2c)(6a - b)$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Multiply the following: $(p + 6), (q - 7)$
→Divide $\left(-121 p^3 q^3 r^3\right)$ by $\left(-11 x y^2 z^3\right)$.
→What is a regular polygon? State the name of a regular polygon of $3$ sides.
→Represent the following numbers on the number line. $2\frac{2}{5}$
→Sobi types $108$ words in $6$ minutes. How many words would she type in half an hour?
→Find $x$, if $\Big(\frac{2}{5}\Big)^{-3}\times\Big(\frac{2}{5}\Big)^{15}=\Big(\frac{2}{5}\Big)^{2+3\text{x}}$
→Find the number of faces in the given shapes:
Express: $56\%$ as a ratio.
→Factorise:
$9a(3a - 5b) - 12a^2(3a - 5b)$
→$9a(3a - 5b) - 12a^2(3a - 5b)$
What is the smallest number by which the following number must be multiplied, so that the products are perfect cube$?\ 1323$
→