Gujarat BoardEnglish MediumSTD 8MATHSFactorisation2 Marks
Question
Divide $\left(-121 p^3 q^3 r^3\right)$ by $\left(-11 x y^2 z^3\right)$.
✓
Answer
We have. $ \begin{array}{l} \left(-121 p^{3} q^{3} r^3\right)+\left(-11 \times y^2 z^3\right) \\ =\frac{-121 p^{3} q^{3} r^{3}}{-11 \times y^2 z^3} \\ =\frac{-11 \times 11 \times p \times p \times p \times q \times q \times q \times r \times+\times r}{-11 \times x \times y \times y \times z \times z \times z} \\ =\frac{11 \times p \times p \times p \times q \times q \times q \times r \times r \times r}{x \times y \times y \times z \times z \times z} \\ =\frac{11 p^3 q^3 r^3}{x y^2 z^3} . \end{array} $
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