Question
Factorise:
$6 p^2+11 p-10$

Answer

$6 p^2+11 p-10$
$=6 x^2+15 x-4 x-10$
$\{6 \times(-10)=60,-60=15 \times(-4), 11=15-4\}$
$=3 x(2 x+5)-2(2 x+5)$
$=(3 x-2)(2 x+5)$

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