Question
Factorise:
$6 x^2-17 x-3$

Answer

$6 x^2-17 x-3$
$=6 x^2-18 x+x-3$
$\{6 × (-3) = -18, -18 = -18 × 1, -17 = -18 + 1\}$
$= 6x(x - 3) + 1(x - 3)$
$ = (x - 3)(6x + 1)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free