Question
Find a repeater machine that will do the same work as a $\big(\text{x}\frac{1}{8}\big)$ machine.

Answer

Since, $\frac{1}{8} \ \text{are} \ \frac{1}{2},\frac{1}{2},\frac{1}{2}.$
So, $\frac{1}{8}=\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}=\big(\frac{1}{2}\big)^3$
Hence, $\big(\text{x}\frac{1}{2^3}\big)$ repeater machine can do the same work as a $\big(\text{x}\frac{1}{8}\big)$ machine.

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