Question
Factorise: $7 x^2-19 x-6$
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Answer
$7 x^2-19 x-6$
$=7 x^2-21 x+2 x-6$
${7 × (-6) = -42, -42 = -21 × 2, -19 = -21 + 2}$
$= 7x(x - 3) + 2(x - 3) $
$= (x - 3)(7x + 2)$
$=7 x^2-21 x+2 x-6$
${7 × (-6) = -42, -42 = -21 × 2, -19 = -21 + 2}$
$= 7x(x - 3) + 2(x - 3) $
$= (x - 3)(7x + 2)$
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