Question
Factorise:
$7 x^2-19 x-6$
$7 x^2-19 x-6$
✓
Answer
$7 x^2-19 x-6$
$=7 x^2-21 x+2 x-6$
$\{7 \times(-6)=-42,-42=-21 \times 2,-19=-21+2\}$
$=7 x(x-3)+2(x-3)$
$=(x-3)(7 x+2)$
$=7 x^2-21 x+2 x-6$
$\{7 \times(-6)=-42,-42=-21 \times 2,-19=-21+2\}$
$=7 x(x-3)+2(x-3)$
$=(x-3)(7 x+2)$
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