Question
Factorise:
$7 y^2-19 y-6$
$7 y^2-19 y-6$
✓
Answer
$7 y^2-19 y-6$
$=7 y^2-21 y+2 y-6$
$\{7 × (-6) = -42, -42 = -21 × 2, -19 = -21 + 3\}$
$= 7y(y - 3) + 2(y - 3) $
$= (y - 3)(7y + 2)$
$=7 y^2-21 y+2 y-6$
$\{7 × (-6) = -42, -42 = -21 × 2, -19 = -21 + 3\}$
$= 7y(y - 3) + 2(y - 3) $
$= (y - 3)(7y + 2)$
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