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Linear Equations in One Variable — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSLinear Equations in One Variable2 Marks
Question
Solve $0.44 t-1.05=2(0.71 t-0.01)+1.11$
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Answer

We have,
$0.44 t-1.05=2 \times 0.71 t-2 \times 0.01+1.11$
$\Rightarrow \quad 0.44 t-1.05=1.42 t-0.02+1.11$
$\Rightarrow \quad 0.44 t-1.42 t=1.05-0.02+1.11\quad$ [transposing 1.42 t to LHS and -1.05 to RHS]
$\Rightarrow \quad-0.98 t=2.14$
$\Rightarrow \quad t=\frac{2.14 \times 100}{-0.98 \times 100} \Rightarrow t=\frac{214}{-98}=\frac{-107}{49}$

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