Question
Factorise:
$9 m^2+24 m+16$
$9 m^2+24 m+16$
✓
Answer
$9 m^2+24 m+16$
$=9(3 m)^2+2 \times 3 m \times 4+(4)^2] $
$ =(3 m+4)^2 $
$\{\therefore a2 + 2ab + b2 = (a + b)2\}$
$=9(3 m)^2+2 \times 3 m \times 4+(4)^2] $
$ =(3 m+4)^2 $
$\{\therefore a2 + 2ab + b2 = (a + b)2\}$
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