Question
Factorise the expression $121b^2– 88bc + 16c^2$
✓
Answer
$121b^2– 88bc + 16c^2$
$= (11b)^2– 2(11b) (4c) + (4c)^2$
$= (11b – 4c)^2. . . . [$Using Identity $II]$
$= (11b)^2– 2(11b) (4c) + (4c)^2$
$= (11b – 4c)^2. . . . [$Using Identity $II]$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Find the area of quadrilateral $PQRS$ shown in Fig.
→Look at the shapes given below and state these are polyhedra using Euler’s formula.
Find the measure of each exterior angle of a regular: Heptagon.
Simplify: $ a^2 b\left(a-b^2\right)+a b^2\left(4 a b-2 a^2\right)-a^3 b(1-2 b) $
→Factorise: $p^2-4 p-11$
→Find the square root in decimal form:$0.00038809$
→Using suitable identities, evaluate the following.
$10.1 × 10.2$
→$10.1 × 10.2$
Factorise the following expressions. $l^2m^2n - lm^2n^2- l^2mn^2$
→Arrange the numbers $\frac{1}{4},\frac{13}{16},\frac{5}{8}$ in the descending order.
→$\frac{1}{6}$ of the class students are above average, $\frac{1}{4}$ are average and rest are below average. If there are $48$ students in all, how many students are below average in the class?
→