Question
Factorise:
$9 x^2+18 x+8$
$9 x^2+18 x+8$
✓
Answer
$9 x^2+18 x+8$
$=9 x^2+12 x+6 x+8$
$=3 x(3 x+4)+2(3 x+4)$
$=(3 x+4)(3 x+2)$
$=9 x^2+12 x+6 x+8$
$=3 x(3 x+4)+2(3 x+4)$
$=(3 x+4)(3 x+2)$
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