Question
Factorise: $9x^2y^2– 16$
✓
Answer
$9x^2y^2–16$
$= (3xy)^2– (4)^2$
$= (3xy – 4) (3xy + 4). . . . $[Using Identity]
$= (3xy)^2– (4)^2$
$= (3xy – 4) (3xy + 4). . . . $[Using Identity]
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