Question
Factorise:
$a^3-0.064$

Answer

$a^3-0.064$
$=(a)^3-(0.4)^3$
$=(a-0.4)\left[(a)^2+a \times 0.4+(0.4)^2\right] \text { Since } a^3-b^3=(a-b)\left(a^2+a \times b+b^2\right)$
$=(a-0.4)\left(a^2+0.4 a+0.16\right)$

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