Question
Factorise:
a3 + 3a2b + 3ab2 + b3 - 8

Answer

a3 + 3a2b + 3ab2 + b3 - 8
= (a + b)3 - 23
=[(a + b) - 2][(a + b)2 + (a + b)2 + 22]
=(a + b - 2)[(a + b)2 + 2(a + b) + 4]

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