Question
Factorise:
a3 + 8b3 + 64c3 - 24abc

Answer

a3 + 8b3 + 64c3 - 24abc
= a3 + (2b)3 + (4c)3 - 3 × a × 2b × 4c
= (a + 2b + 4c)[a2 + (2b)2 + (4c)2 - a × 2b - 2b × 4c - 4c × a]
= (a + 2b + 4c)(a2 + 4b2 + 16c2 - 2ab - 8bc - 4ca)

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