Question
Factorise by the grouping method $: (2a-b)^2-10a + 5b$
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Answer
$( 2a - b)^2 - 10a + 5b$
$= ( 2a - b )^2 - 5( 2a - b )$
$= ( 2a - b )( 2a - b - 5 )$
$= ( 2a - b )^2 - 5( 2a - b )$
$= ( 2a - b )( 2a - b - 5 )$
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