Factorise by the grouping method : a^4- 2a^3- 4a + 8 - Vidyadip

Question

Factorise by the grouping method : $a^4- 2a^3- 4a + 8$

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Answer

$a^4- 2a^3 - 4a + 8$
$= a^3( a - 2 ) - 4( a - 2 )$
$= ( a^3 - 4 )( a - 2 )$

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