[1 Mark Question Answer]

Questions

🎯

6 questions · timed · auto-graded

Question 11 Mark

Factorise : $1 - 2a - 3a^2$

Answer

$1 - 2a - 3a^2$
$= 1 - 3a + a - 3a2$
$=( 1 + a )( 1 - 3a )$

Question 21 Mark

Factorise : $a^2- 3a - 40$

Answer

$a^2 - 3a - 40$
$= a^2 - 8a + 5a - 40$
$= a( a - 8 ) + 5( a - 8 )$
$= ( a - 8 )( a + 5 )$

Question 31 Mark

Factorise : $a^2+ 10a + 24$

Answer

$a^2 + 10a + 24$
$= a^2 + 6a + 4a + 24$
$= a( a + 6 ) + 4( a + 6 )$
$= ( a + 6 )( a + 4 )$

Question 41 Mark

Factorise by the grouping method : $ab- 2b + a^2- 2a$

Answer

$ab- 2b + a^2 - 2a$
$= b( a - 2 ) + a( a - 2 )$
$= ( a + b )( a - 2 )$

Question 51 Mark

Factorise by the grouping method : $a^4- 2a^3- 4a + 8$

Answer

$a^4- 2a^3 - 4a + 8$
$= a^3( a - 2 ) - 4( a - 2 )$
$= ( a^3 - 4 )( a - 2 )$

Question 61 Mark

Factorise by the grouping method :$ a (a -4) - a + 4$

Answer

$a (a -4) - a + 4$
$= a( a - 4 ) -1( a - 4 )$
$= ( a - 4 )( a - 1 )$

[1 Mark Question Answer] - MATHEMATICS STD 9 Questions - Vidyadip

MATHEMATICS [1 Mark Question Answer]