Question
Factorise: $(l+m)^2-41 m$
✓
Answer
$(l+m)^2-41 m$
$=l^2+m^2+21 m-41 m$
$=l^2+m^2-21 m=l^2-21 m+m^2$
$=(l-m)^2$
$\{\because a^2+ 2ab + b^2= (a + b)^2\}$
$=l^2+m^2+21 m-41 m$
$=l^2+m^2-21 m=l^2-21 m+m^2$
$=(l-m)^2$
$\{\because a^2+ 2ab + b^2= (a + b)^2\}$
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