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Understanding Shapes – II (Special Types of Quadrilaterals) — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSUnderstanding Shapes – II (Special Types of Quadrilaterals)2 Marks
Question
Given below is a parallelogram $\text{ABCD}$. Complete each statement along with the definition or property used.
$i. \text{AD}=$
$ii. \angle\text{DCB}=$
$iii. \text{OC}=$
$iv. \angle\text{DAB}+\angle\text{CDA}=$
✓

Answer

The correct figure is

$i. \text{AD = BC} ($opposite sides of a parallelogram are equal$)$
$ii. \angle\text{DCB}=\angle\text{BAD} ($opposite angles are equal$)$
$iii. \text{OC = OA} ($diagonals of a prallelogram bisect each other$)$
$iv. \angle\text{DAB}+\angle\text{CDA}=180^\circ ($the sum of two adjacent angles of a paralleloram is $180^\circ .)$

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