Question
Factorise: $m^2-4 m n+4 n^2$
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Answer
$m^2-4 m n+4 n^2$
$=(m)^2-2 \times m \times 2 n+(2 n)^2$
$=(m-2 n)^2$
$=(m)^2-2 \times m \times 2 n+(2 n)^2$
$=(m-2 n)^2$
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