Question
Write a pythagorean triplet whose smallest member is:$ 6$

Answer

For every natural number $m>1,\left(2 m, m^2-1, m^2+1\right)$ is a Pythagorean triplet.
Putting $2m = 6$
We get $m = 3$
Thus, we get the triplet $(6, 8, 10).$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free