Question
Factorise: $p^2-4 p-11$

Answer

$p^2-4 p-11$
$=p^2+11 p-7 p-77$
${-77 = -11 × 7, -4 = -11 + 7}$
$= p(p - 11) + 7(p - 11) $
$= (p - 11)(p + 7)$

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