Question
Factorise:
$p^2+6 p+8$
$p^2+6 p+8$
✓
Answer
$p^2+6 p+8$
$=p^2+4 p+2 p+8$
$\{8 = 4 × 2, 6 = 4 + 2\}$
$ = p(p + 4) + 2(p + 4) $
$= (p + 4)(p + 2)$
$=p^2+4 p+2 p+8$
$\{8 = 4 × 2, 6 = 4 + 2\}$
$ = p(p + 4) + 2(p + 4) $
$= (p + 4)(p + 2)$
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