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Factorization — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSFactorization3 Marks
Question
Factorise the expressions: $p^2+ 6p + 8$
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Answer

$ p^2+6 p+8 $
$ =p^2+6 p+9-1 $
$ =\left\{(p)^2+2(p)(3)+(3)^2\right\}-(1)^2 $
$ =(p+3)^2-(1)^2 . . . .$ [Using Identity $I$
$= (p + 3 – 1) (p + 3 + 1). . . .$ [Using Identity $III]$
$= (p + 2) (p + 4)$

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