Question
Factorise the following, using the identity $a^2-2 a b+b^2=(a-b)^2$.
$p^2-2 p+1$
$p^2-2 p+1$
✓
Answer
$p^2-2 p+1$
$=p^2-2 \times p \times 1+1^2 $
$ =(p-1)^2 $
$ =(p-1)(p-1)$
$=p^2-2 \times p \times 1+1^2 $
$ =(p-1)^2 $
$ =(p-1)(p-1)$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Simplify: $(3^2-2^2)\times\Big(\frac{2}{3}\Big)^{-3}$
→How many vertices are there in a: Square pyramid?
Is $90$ a perfect square?
→Is $1000$ a perfect cube?
→Factorise: $x^4-(y+z)^4$
→Observe the following pattern and the missing digits.
A dining table is purchased for $Rs.\ 3,200$ and sold at a gain of $6\%$. If a customer pays sales tax at the rate of $5\%$. How much does the customer pay in all for the table?
→Find the scale. Actual size $45$ feet. Drawing size $5$ inches.
→Factorise: $4a^2- 9$
→Rohan can paint $\frac{1}{3}$ of a painting in $6$ days. How many days will he take to complete the painting$?$
→