Question
Is $1000$ a perfect cube?
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Answer
By prime factorisation,
$1000 = 2 \times 2 \times 2 \times 5 \times 5 \times 5 [grouping the factors in triplets]$
$ =2^3 \times 5^3$
$=(2 \times 5)^3=(10)^3$ , which is a perfect cube
All the terms form triplets
Therefore, $1000$ is a perfect cube.
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