Question
Factorise the following, using the identity $a^2-2 a b+b^2=(a-b)^2$.
$p^2 y^2-2 p y+1$
$p^2 y^2-2 p y+1$
✓
Answer
$p^2 y^2-2 p y+1$
$ =(p y)^2-2 \times p y \times 1+1^2 $
$ =(p y-1)^2 $
$ =(p y-1)(p y-1)$
$ =(p y)^2-2 \times p y \times 1+1^2 $
$ =(p y-1)^2 $
$ =(p y-1)(p y-1)$
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