Question
Show that the Cryptarithm $4\times\overline{\text{AB}}=\overline{\text{CAB}}$ does not have any solution.
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Answer
$0$ is the only unit digit number, which gives the same $0$ at the unit digit when multipied by $4.$ So, the possible value of $B$ is $0.$ Similarly, for $A, 0$ is the only possible digit.But then $A, B$ and $C$ will all be $0.$ And if $A, B$ and $C$ become $0,$ these numbers cannot be of two-digit or three-digit. Therefore, both will become a one-digit number.Thus, there is no solution possible.
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