Question
Factorise the following, using the identity $\mathrm{a}^2-2 \mathrm{ab}+\mathrm{b}^2=(\mathrm{a}-\mathrm{b})^2$.
$y^2-14 y+49$
$y^2-14 y+49$
✓
Answer
$y^2-14 y+49$
$ =y^2-2 \times y \times 7+7^2 $
$ =(y-7)^2 $
$=(y-7)(y-7)$
$ =y^2-2 \times y \times 7+7^2 $
$ =(y-7)^2 $
$=(y-7)(y-7)$
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