Question
Factorise the following:$2a^3 + 5a^2b - 12ab^2$

Answer

$2a^3 + 5a^2b - 12ab^2$
$= 2a^3 + 8a^2b - 3a^2b - 12ab^2$
$= 2a^2(a + 4b) - 3ab(a + 4b)$
$= (a + 4b)(2a^2 - 3ab)$
$= (a + 4b)a(2a - 3b)$
$= a(a + 4b)(2a - 3b).$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Draw the graph for the equation given below; hence find the co $-$ ordinates of the points where the graph is drawn meets the co $-$ ordinates axes : $\frac{2 x+15}{3}=y-1$
In the given figure$, \angle B = 60^\circ , AB = 16 \ cm$ and $BC = 23 \ cm,$Calculate $: (i)\ BE, \ (ii)\ AC$
Water flows into a tank 150 m long and 100 m broad through a rectangular pipe whose cross section is 5 dm 3.5 dm, at the speed of 15 km/hr. In what time, will the water be 7 m deep?
A rectangular tank is 25 m long and 7.5 m deep. If 540 $m ^3$ of water be drawn off the tank, the level of water in the tank goes down by 1.8 m.
Calculate : (i) the width of the tank,
(ii) the capacity of the tank.
In $\triangle PQR$ is a triangle and $S$ is any point in its interior. Prove that $SQ + SR < PQ + PR.$
Construct a parallelogram $\text{ABCD},$ when:$AB = 5.8 \ cm,$ diagonal $AC = 8.2 \ cm$ and diagonal $BD = 6.2 \ cm.$
The following figure shows a $\triangle ABC$ in which $P, Q,$ and $R$ are mid$-$points of sides $AB, BC$ and $CA$ respectively. $S$ is mid$-$point of $PQ$:Prove that: $ar. ( \triangle ABC ) = 8 \times ar. ( \triangle QSB )$
If $(a+3 b)=6$, show that $a^3+27 b^3+54 a b=216.$
The following figure shows a square cardboard $\text{ABCD}$ of side $28 \ cm$. Four identical circles of the largest possible sizes are cut from this card as shown below.

Find the area of the remaining card$-$board.
In the figure: $\angle PSQ =90^{\circ}, PQ =10 \ cm , QS =6 \ cm$ and $RQ =9 \ cm$. Calculate the length of $PR.$