Question
Factorize:$21\text{x}^2-2\text{x}+\frac{1}{21}$

Answer

$21\text{x}^2-2\text{x}+\frac{1}{21}$
$=\big(\sqrt{21\text{x}}\big)^2-2\sqrt{21}\text{x}\times\frac{1}{\sqrt{21}}+\Big(\frac{1}{\sqrt{21}}\Big)^2$
Using the identity $(x - y)^2 = x^2 + y^2 - 2xy$
$\Big(\sqrt{21}\text{x}-\frac{1}{\sqrt{21}}\Big)^2$
$\therefore21\text{x}^2-2\text{x}+\frac{1}{21}=\Big(\sqrt{21}\text{x}-\frac{1}{\sqrt{21}}\Big)^2$

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